Let \(x_i\) represent the number of copies sold on the \(i\)th day, and let \(S_n\) denote the total number of copies sold in the first \(n\) days. Step 1: Use the given averages for the first 7 and 8 days. The average number of copies sold during the first 7 days is 60, so \[ S_7 = 7 \times 60 = 420. \] The average for the first 8 days is 63, hence \[ S_8 = 8 \times 63 = 504. \] Step 2: Determine the number of copies sold on the 8th day. \[ x_8 = S_8 - S_7 = 504 - 420 = 84. \] Step 3: Find the sales on the 9th day. It is given that on the 9th day, the sales were 11 fewer than on the 8th day. Therefore, \[ x_9 = x_8 - 11 = 84 - 11 = 73. \] Step 4: Use the average from the 2nd to the 9th day. From day 2 to day 9, there are 8 days, and the average number of copies sold is 66. Thus, \[ S_{2\text{--}9} = 8 \times 66 = 528. \] Step 5: Relate the totals to find the sales on the first day. The total number of copies sold in the first 9 days is \[ S_9 = S_8 + x_9 = 504 + 73 = 577. \] This total can also be expressed as \[ S_9 = x_1 + S_{2\text{--}9} = x_1 + 528. \] Equating the two expressions, \[ x_1 + 528 = 577 \Rightarrow x_1 = 49. \] Hence, the number of copies sold on the first day is \(49\).
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: