The average marks of a student in 10 papers are 80. If the highest and the lowest scores are not considered, the average is 81. If his highest score is 92, find the lowest.
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When removing items from average calculation, adjust the total sum accordingly.
Total marks for 10 papers = $80 \times 10 = 800$.
Removing highest (92) and lowest (L), we have 8 papers average = 81 $\Rightarrow$ total = $81 \times 8 = 648$.
So $800 - 92 - L = 648 \Rightarrow 708 - L = 648 \Rightarrow L = 60$.
Answer = 60 (option b).