Question:

The average (arithmetic mean) of x and y is 40. If z = 10, then what is the average of x, yand z?

Updated On: Oct 1, 2024
  • \(16\frac{2}{3}\)
  • 30
  • 25
  • \(17\frac{1}{2}\)
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The Correct Option is B

Solution and Explanation

The correct option is (B): 30
Given that: arithmetic mean of \(x \space and \space y= 40\)
\(⇒\)\(\frac{x+y}{2}=40\)  ⇒ \(x+y=80\)
given that \(z=10\)
so A.M of \(x,y,z =\frac{x+y+z}{3}\)
\(⇒\)\(\frac{80+10}{3}\)\(= 30\)

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