For Solving this problem we use Newton's second law of motion(\(F=m\times a)\)
Acc. to Ques:
- \(m = 1000 \, \text{kg}\)
- \(a = 1 \, \frac{m}{s^2}\)
So, \(F = 1000 \, \text{kg} \cdot 1 \, \frac{m}{s^2} = 1000 \, \text{N}\)
-We know that \((1 \, \text{N} \approx 0.2248 \, \text{lbs})\)
\(F \text{ (in pounds)} = 1000 \, \text{N} \times 0.2248 \, \frac{\text{lbs}}{\text{N}} \approx 224.8 \, \text{lbs}\)
Therefore, The correct option is (C).