1 candle is made from 9 stubs, \(\rightarrow\) 116 candles will be made from 1044 stubs.
From 116 candles, 12 candles can be made with 8 stubs left.
Now total stubs left =12 +8 = 20, out of which two candles can be made with two stubs left.
Thus, Maximum number of candles that can be made = (116 + 12 + 2) =130
The correct answer is (C) :130