To solve this problem, we need to know the atomic radii of the elements magnesium (Mg), phosphorus (P), silicon (Si), and aluminum (Al).
1. Atomic Radii Trend:
The atomic radius generally decreases across a period from left to right and increases down a group. Based on this trend and the known atomic radii of these elements:
2. Analyzing the Options:
Option 1: 160, 143, 117, 110 (incorrect order).
Option 2: 110, 117, 143, 160 (incorrect order).
Option 3: 160, 110, 117, 143 (correct order).
This follows the atomic radius trend correctly, with magnesium having the largest atomic radius, followed by aluminum, silicon, and phosphorus
Option 4: 110, 160, 143, 117 (incorrect order).
3. Conclusion:
Based on the correct atomic radius order for these elements, the correct answer is Option C.
Final Answer:
The correct answer is Option C: 160, 110, 117, 143.
The density of \(\beta\)-Fe is 7.6 g/cm\(^3\). It crystallizes in a cubic lattice with \( a = 290 \) pm.
What is the value of \( Z \)? (\( Fe = 56 \) g/mol, \( N_A = 6.022 \times 10^{23} \) mol\(^{-1}\))
Arrange the following in the increasing order of number of unpaired electrons present in the central metal ion:
I. \([MnCl_6]^{4-}\)
II. \([FeF_6]^{3-}\)
III. \([Mn(CN)_6]^{3-}\)
IV. \([Fe(CN)_6]^{3-}\)