Question:

The argument of the complex number $ \left( \frac{i}{2}-\frac{2}{i} \right) $ is equal to

Updated On: Jun 8, 2024
  • $ \frac{\pi }{4} $
  • $ \frac{3\pi }{4} $
  • $ \frac{\pi }{12} $
  • $ \frac{\pi }{2} $
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The Correct Option is D

Solution and Explanation

Let $ z=\frac{i}{2}-\frac{2}{i}=\frac{i}{2}-\frac{2i}{{{i}^{2}}} $ $ Z=\frac{i}{2}+2i=\frac{5}{2}i=0+\frac{5}{2}i $ $ \arg (z)={{\tan }^{-1}}\left( \frac{\operatorname{Im}(z)}{\operatorname{Re}(z)} \right) $
$={{\tan }^{-1}}\left( \frac{5/2}{0} \right)={{\tan }^{-1}}(\infty ) $
$={{\tan }^{-1}}\left( \tan \frac{\pi }{2} \right)=\frac{\pi }{2} $
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Concepts Used:

Quadratic Equations

A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers

Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.

The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)

Two important points to keep in mind are:

  • A polynomial equation has at least one root.
  • A polynomial equation of degree ‘n’ has ‘n’ roots.

Read More: Nature of Roots of Quadratic Equation

There are basically four methods of solving quadratic equations. They are:

  1. Factoring
  2. Completing the square
  3. Using Quadratic Formula
  4. Taking the square root