Since the −NH2 group is ortho/para directing, the arenium ion will not be formed by attack at the meta position. This is due to the electron-donating nature of the −NH2 group, which stabilizes the carbocation at the ortho and para positions relative to itself.
Thus, the arenium ion corresponding to the meta substitution, as shown in answer (3), does not participate in the bromination of aniline.
So, the correct answer is: Option (3)
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |
List-I | List-II | ||
(A) | [Co(NH3)5(NO2)]Cl2 | (I) | Solvate isomerism |
(B) | [Co(NH3)5(SO4)]Br | (II) | Linkage isomerism |
(C) | [Co(NH3)6] [Cr(CN)6] | (III) | Ionization isomerism |
(D) | [Co(H2O)6]Cl3 | (IV) | Coordination isomerism |