The perimeter of a square is given as 224 cm. To find the side length of the square, we use the formula for the perimeter of a square which is \( P = 4s \), where \( s \) is the side length.
\( s = \frac{224}{4} = 56 \) cm
Now, the area of the square is \( s^2 \).
\( \text{Area of square} = 56 \times 56 = 3136 \text{ cm}^2 \)
According to the problem, the area of the triangle is half of the area of the square.
\( \text{Area of triangle} = \frac{3136}{2} = 1568 \text{ cm}^2 \)
The area of the triangle is therefore 1568 cm2.
Find the missing code:
L1#1O2~2, J2#2Q3~3, _______, F4#4U5~5, D5#5W6~6