Question:
The area of the region bounded by the curve \(y=\sqrt{3x+10}\), x-axis and between the lines x = -3 and x = 2 is equal to :
The area of the region bounded by the curve \(y=\sqrt{3x+10}\), x-axis and between the lines x = -3 and x = 2 is equal to :
Updated On: Jun 13, 2024
- \(\frac{110}{9}\)
- \(\frac{252}{9}\)
- \(\frac{114}{9}\)
- \(\frac{126}{9}\)
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The Correct Option is D
Solution and Explanation
The correct option is (D) :\(\frac{126}{9}\).
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