Question:

The area of a rectangle is 48 cm$^2$, and its perimeter is 28 cm. What is the length of the rectangle?

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Form a quadratic equation using area and perimeter to find rectangle dimensions.
Updated On: Jul 29, 2025
  • 6 cm
  • 8 cm
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The Correct Option is B

Solution and Explanation

- Step 1: Let length = $l$, breadth = $b$. Given: $lb = 48$, $2(l + b) = 28 \implies l + b = 14$.
- Step 2: Solve: $b = 14 - l$, substitute in $lb = 48$: $l(14 - l) = 48 \implies 14l - l^2 = 48 \implies l^2 - 14l + 48 = 0$.
- Step 3: Solve quadratic: $l = \frac{14 \pm \sqrt{196 - 192}}{2} = \frac{14 \pm 2}{2}$, so $l = 8$ or $l = 6$.
- Step 4: If $l = 8$, $b = 14 - 8 = 6$. Area = $8 \times 6 = 48$, perimeter = $2(8 + 6) = 28$. Matches.
- Step 5: If $l = 6$, $b = 8$, same result. Since length $\geq$ breadth, take $l = 8$.
- Step 6: Option (2) is 8 cm, correct.
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