Question:

The area enclosed between the curve \( y = \log_e(x + e) \) and the coordinate axes is:

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For finding the area under curves involving logarithms, use substitution and evaluate the integral carefully, keeping in mind the behavior of the logarithmic function at both the upper and lower limits.
Updated On: Mar 26, 2025
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The Correct Option is A

Solution and Explanation

 

Required area \[ A = \int_{1 - e}^{0} y \, dx = \int_{1 - e}^{0} \log_e (x + e) \, dx \] Put \( x + e = t \Rightarrow dx = dt \), also when \( x = 1 - e \), \( t = 1 \) and when \( x = 0 \), \( t = e \). \[ \therefore A = \int_{1}^{e} \log_e t \, dt = \left[ t \log_e t - t \right]_{1}^{e} \] \[ e - e - 0 + 1 = 1 \]
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