Let the height of the multi-storeyed building be h, and the distance between the two buildings be d.
1. Using the angle of depression of 45°:
\[ \tan(45^\circ) = \frac{8}{d_1} \]
Since \(\tan(45^\circ) = 1\), we have:
\[ d_1 = 8 \, \text{m} \]
This is the horizontal distance from the base of the multi-storeyed building to the base of the 8 m tall building.
2. Using the angle of depression of 30°:
\[ \tan(30^\circ) = \frac{h - 8}{d_1 + 14} \]
Substituting \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\) and \(d_1 = 8\):
\[ \frac{1}{\sqrt{3}} = \frac{h - 8}{8 + 14} \]
Simplifying:
\[ \frac{1}{\sqrt{3}} = \frac{h - 8}{22} \]
\[ h - 8 = \frac{22}{\sqrt{3}} \approx 12.67 \]
Therefore:
\[ h = 8 + 12.67 = 20.67 \, \text{m} \]
Thus, the height of the multi-storeyed building is approximately 20.67 m, and the distance between the two buildings is 14 m.
सड़क सुरक्षा के प्रति जागरूकता हेतु ट्रैफिक पुलिस की ओर से जनहित में जारी एक आकर्षक विज्ञापन लगभग 100 शब्दों में तैयार कीजिए।
Proteins control the expression of various characters. Explain this statement by taking an example of "tallness" as a characteristic in plants
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