Question:
The amphoteric oxide of Vanadium (V) reacts with alkali and forms an oxoion \( X \) and with acid forms an oxoion \( Y \). The oxidation states of \( V \) in \( X \) and \( Y \) are respectively:
The amphoteric oxide of Vanadium (V) reacts with alkali and forms an oxoion \( X \) and with acid forms an oxoion \( Y \). The oxidation states of \( V \) in \( X \) and \( Y \) are respectively:
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Vanadium pentoxide is amphoteric, reacting with both acids and bases, forming oxoions while retaining oxidation state +5.
Updated On: Jun 5, 2025
- \( +2, +5 \)
- \( +3, +3 \)
- \( +5, +5 \)
- \( +5, +2 \)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding Amphoteric Behavior of Vanadium Oxide
Vanadium pentoxide (\( V_2O_5 \)) is amphoteric, meaning it reacts with both acids and bases.
Step 2: Oxoions Formation
- In alkali (\( NaOH \)), vanadium forms vanadate ions \( VO_4^{3-} \) with oxidation state +5.
- In acid (\( H^+ \)), vanadium forms vanadyl ions \( VO_2^+ \), also with oxidation state +5.
Conclusion
Thus, the correct answer is:
\[
+5, +5
\]
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