Question:

The amount of sugar $ {(C_{12}H_{22}O_{11})}$ required to prepare $2\, L$ of its $0.1\, M$ aqueous solution is :

Updated On: Aug 21, 2024
  • 68.4 g
  • 17.1 g
  • 34.2g
  • 136.8 g
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The Correct Option is A

Solution and Explanation

$Molarity = \frac{\left(n\right)_{\text{solute}}}{V_{\text{solution}} \left(\text{in} \text{lit}\right)} $ $ 0.1 = \frac{wt. /342}{2} $ $wt\left(C_{12}H_{22}O_{11}\right) = 68.4\, \text{gram} $
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Concepts Used:

Concentration of Solutions

It is the amount of solute present in one liter of solution.

Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.

Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).

Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage

Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.

Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.

Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.

Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.

Formality - It is the number of gram formula present in one litre of solution.