Question:

The additional kinetic energy to be provided to a satellite of mass $m$ revolving around a planet of mass $M$ to transfer it from a circular orbit of radius $R_1$ to another of radius $R_2$ $(R_2 > R_1)$ is

Updated On: Jul 13, 2024
  • $GmM\left(\frac{1}{R^{2}_{1}}-\frac{1}{R^{2}_{2}}\right)$
  • $GmM\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)$
  • $2GmM\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)$
  • $\frac{1}{2}GmM\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)$
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The Correct Option is D

Solution and Explanation

As$-\frac{GMm}{2R_{1}}+KE=\frac{-GMm}{2R_{2}}$
$\quad\quad\quad\therefore\quad KE=\frac{1}{2}GMm\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right).$
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Concepts Used:

Escape Speed

Escape speed is the minimum speed, which is required by the object to escape from the gravitational influence of a plannet. Escape speed for Earth’s surface is 11,186 m/sec. 

The formula for escape speed is given below:

ve = (2GM / r)1/2 

where ,

ve = Escape Velocity 

G = Universal Gravitational Constant 

M = Mass of the body to be escaped from 

r = Distance from the centre of the mass