The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2m on the surface of A. What is the height of jump by the same person on the planet B.
- \(\frac 29 \ m\)
- \(18\ m\)
- \(6\ m\)
- \(\frac {2}{3 }\ m\)
The Correct Option is B
Solution and Explanation
Height of jump on the planet B;
\(h_b\) =\(\frac {g_A}{g_B}\)× height of jump on the planet A (∴ mgh = constant)
\(h_b = \frac {9}{1} \times 2\)
\(h_b = 18 \ m\)
So, the correct option is (B): 18 m
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Concepts Used:
Acceleration
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.
