Question:

The ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. I$_{AB}$, I$_{BC}$ and I$_{CA}$ are the moments of inertia of the plate about AB, BC and CA respectively. Which one of the following relations one is correct ?

Updated On: Aug 18, 2024
  • $I_{AB}+I_{BC}=I_{CA}$
  • $I_{CA}$ is maximum
  • $I_{AB} > I_{BC}$
  • $I_{BC} > I_{AB}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

The intersection of medians is the centre of mass of the triangle. Since the distances of centre of mass from the sides is related as x$_{BC} < x_{AB} < x _{AC}$.
Therefore I$_{BC}$ > I$_{AB}$ > I$_{AC}$ or I$_{BC}$ > I$_{AB}$ .
Was this answer helpful?
0
0

Concepts Used:

Center of Mass

The center of mass of a body or system of a particle is defined as a point where the whole of the mass of the body or all the masses of a set of particles appeared to be concentrated.

The formula for the Centre of Mass:

Center of Gravity

The imaginary point through which on an object or a system, the force of Gravity is acted upon is known as the Centre of Gravity of that system. Usually, it is assumed while doing mechanical problems that the gravitational field is uniform which means that the Centre of Gravity and the Centre of Mass is at the same position.