Non-polar molecules have a symmetrical arrangement of atoms that results in no net dipole moment. In the given list: - \(CO_2\) is linear and symmetrical, so it is non-polar. - \(H_2\) is diatomic and non-polar because it is composed of identical atoms. - \(CH_4\) has a tetrahedral geometry with symmetrical bond distribution, making it non-polar. - \(BF_3\) has a trigonal planar geometry, which is symmetrical and therefore non-polar.
Other molecules like HF, \(H_2O\), \(SO_2\), \(NH_3\), HCl, and \(CHCl_3\) are polar due to their asymmetrical shapes or differences in electronegativity. Therefore, there are four non-polar molecules in the list.
The Correct answer is: 4
Match the LIST-I with LIST-II:
Choose the correct answer from the options given below :
The number of molecules/ions that show linear geometry among the following is _____. SO₂, BeCl₂, CO₂, N₃⁻, NO₂, F₂O, XeF₂, NO₂⁺, I₃⁻, O₃
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32