
To determine who envies someone else, we need to analyze the information and constraints given regarding how each person values their bundles:
| o1 | o2 | o3 | o4 | o5 | o6 | o7 | o8 | o9 | o10 | |
|---|---|---|---|---|---|---|---|---|---|---|
| Amar | 4 | 9 | 9 | 5 | 5 | 10 | 8 | 7 | 9 | 7 |
| Barat | 7 | 6 | 4 | 6 | 10 | 5 | 6 | 9 | 8 | 7 |
| Charles | 6 | 6 | 9 | 10 | 6 | 6 | 7 | 6 | 6 | 8 |
| Disha | 5 | 5 | 6 | 5 | 6 | 5 | 6 | 6 | 10 | 4 |
| Elise | 9 | 10 | 5 | 6 | 5 | 6 | 6 | 6 | 5 | 7 |
Amar, after evaluating all conditions, envies Elise since her value is greater than his bundle ({o6, o3}).
To determine Amar’s value for his own bundle, follow these logical steps
| Object | Amar | Barat | Charles | Disha | Elise |
|---|---|---|---|---|---|
| o1 | 10 | 5 | 7 | 6 | 9 |
| o2 | 9 | 6 | 5 | 10 | 4 |
| o3 | 8 | 10 | 3 | 6 | 5 |
| o4 | 7 | 8 | 9 | 5 | 10 |
| o5 | 6 | 7 | 10 | 3 | 8 |
| o6 | 5 | 9 | 8 | 7 | 6 |
| o7 | 4 | 4 | 6 | 9 | 7 |
| o8 | 3 | 3 | 4 | 8 | 9 |
| o9 | 2 | 2 | 8 | 9 | 4 |
| o10 | 1 | 1 | 2 | 4 | 3 |
Therefore, Amar's value for his own bundle is 12.
To determine who received object o4, we examine the conditions and constraints of the problem.
First, consider the rule: If someone’s value for an object is 10, then she/he received that object. Using this, identify the assignments:
Next, analyze the pairs: Objects o1, o2, and o3 were given to different people. Objects o1 and o8 were given to different people. Use the condition that three people value their own bundles at 16, and one person values at an odd number.
Finally, to determine who received o4, the logical deduction enforces that Barat is the recipient of o4 due to the paired allocations and values that meet the conditions.
However, after considering constraints, repositioning, and reevaluations, Disha receives o4 to maintain the odd bundle, providing a final correct analysis.
Therefore, object o4 was given to Disha.
Bundle Calculations:
To determine the distribution of object o1, we must use the given clues effectively:





For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: