Let the total work be \( W \) (in terms of work units).
The team members can complete the work in 20 days, so their rate of work is:
\[ \text{Rate of work of team members} = \frac{W}{20} \]
With the help of their team leader, they can complete the work in 15 days. Hence, the combined rate of work is:
\[ \text{Combined rate of work} = \frac{W}{15} \]
Let the rate of work of the team leader be \( x \). Then, we have the equation:
\[ \frac{W}{20} + x = \frac{W}{15} \]
Solving for \( x \):
\[ x = \frac{W}{15} - \frac{W}{20} \]
Taking LCM of 15 and 20, we get: \[ x = W \left(\frac{1}{15} - \frac{1}{20} \right) \]
\[ x = W \left(\frac{4}{60} - \frac{3}{60} \right) = W \times \frac{1}{60} \]
The team leader alone can complete the total work \( W \) at a rate of \( W/60 \) per day, so the total time required is:
\[ \frac{W}{W/60} = 60 \text{ days} \]
Thus, the team leader alone can complete the job in 60 days. The correct answer is (C) 60 days.