Question:

Suppose that two persons $A$ and $B$ solve the equation $ {{x}^{2}}+ax+b=0 $ . While solving $A$ commits a mistake in the coefficient of $ x $ was taken as $15$ in place of $-9$ and finds the roots as $ -7 $ and $ -2 $ . Then, the equation is

Updated On: Jun 7, 2024
  • $ {{x}^{2}}+9x+14=0 $
  • $ {{x}^{2}}-9x+14=0 $
  • $ {{x}^{2}}+9x-14=0 $
  • $ {{x}^{2}}-9x-14=0 $
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The Correct Option is B

Solution and Explanation

Let the incorrect equation is $ {{x}^{2}}+15x+b=0 $ .
Since, roots are $ -7 $ and $ -2 $ .
$ \therefore $ Product of roots, $ b=14 $
So, correct equation is $ {{x}^{2}}-9x+14=0 $
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Concepts Used:

Quadratic Equations

A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers

Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.

The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)

Two important points to keep in mind are:

  • A polynomial equation has at least one root.
  • A polynomial equation of degree ‘n’ has ‘n’ roots.

Read More: Nature of Roots of Quadratic Equation

There are basically four methods of solving quadratic equations. They are:

  1. Factoring
  2. Completing the square
  3. Using Quadratic Formula
  4. Taking the square root