The total number of possible outcomes when flipping six coins=\(2^6=64\)
Probability that no tail occurs=\(\frac{1}{64}\)
So, Probability of occurring at least one tail=\(1-\frac{1}{64}\)\(=\frac{63}{64}\)
The correct option is (C): \((\frac{63}{44})\)
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
