The total number of possible outcomes when flipping six coins=\(2^6=64\)
Probability that no tail occurs=\(\frac{1}{64}\)
So, Probability of occurring at least one tail=\(1-\frac{1}{64}\)\(=\frac{63}{64}\)
The correct option is (C): \((\frac{63}{44})\)
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
