Institute | M:F |
P | 7:9 |
Q | 5:4 |
R | 5:7 |
S | 6:5 |
T | 3:5 |
U | 7:4 |
V | 7:5 |
Total number of students = 4,800
The required percentage is:
\[ \frac{576}{384} \times 100 \]
\[ = 1.5 \times 100 = 150\% \]
Thus, the correct answer is 150% (Option A).
Let the total number of students in each institute be a multiple of \( x \).
Total students in Institutes Q and V:
\[ 9x + 12x = 21x \]
Total students in Institutes S and T:
\[ 11x + 8x = 19x \]
The required percentage is:
\[ \frac{\text{Total students in Q and V}}{\text{Total students in S and T}} \times 100 \]
\[ \frac{21x}{25x} \times 100 \]
\[ = \frac{21}{25} \times 100 = 83.33\% \]
Thus, the correct answer is 83.33% (Option C).
Total number of students = 4,800
The percentage increase is given by:
\[ \frac{\text{Increase in students}}{\text{Original number of students}} \times 100 \]
Substituting the values:
\[ \frac{768 - 528}{528} \times 100 \]
\[ = \frac{240}{528} \times 100 \]
\[ \approx 45.45\% \]
Thus, the correct answer is 45% (Option D).