Assume the number of students in each row be \(x\)
the number of rows be \(y\)
So, the total number of students will be \(x \times y\)
According to Case number 1,
\((x + 4 ) \times (y - 2) = xy\)
\(xy - 2x + 4y - 8 = xy\)
\(2y - x = 4\) – (i)
According to Case number 2,
\((x - 4 ) \times (y + 4) = xy\)
\(xy + 4x - 4y - 16 = xy\)
\(x - y = 4\) – (ii)
By Adding the equation (i) and (ii) we get,
\(y = 8\)
Putting the value of \(y\) in equation (ii)
\(x\) = 8 + 4
\(x = 12\)
So, the total number of students will be 12 × 8
= 96
The correct option is (C): 96