Number of students per Teacher | Number of Schools |
20 - 25 | 5 |
25 - 30 | 15 |
30 - 35 | 25 |
35 - 40 | 30 |
40 - 45 | 15 |
45 - 50 | 10 |
The cumulative frequency is calculated as follows: \[ \begin{array}{|c|c|c|} \hline \textbf{Class} & \textbf{Frequency (f)} & \textbf{Cumulative Frequency} \\ \hline 20 - 25 & 5 & 5 \\ 25 - 30 & 15 & 20 \\ 30 - 35 & 25 & 45 \\ 35 - 40 & 30 & 75 \\ 40 - 45 & 15 & 90 \\ 45 - 50 & 10 & 100 \\ \hline \end{array} \] Since $n/2 = 100/2 = 50$, the median class is $35 - 40$. Correct Answer: The lower limit of the median class is $35$.
The modal class corresponds to the highest frequency, which is $30$ for the class $35 - 40$.
The upper limit of the modal class is:
Correct Answer: $40$.
\[ \text{Median} = l + \left( \frac{\frac{n}{2} - CF}{f_m} \right) \times h, \] where: $l = 35$ (lower limit of the median class), $n = 100$ (total frequency), $CF = 45$ (cumulative frequency of the class before the median class), $f_m = 30$ (frequency of the median class), $h = 5$ (class width). Substituting: \[ \text{Median} = 35 + \left( \frac{50 - 45}{30} \right) \times 5 = 35 + \left( \frac{5}{30} \right) \times 5 = 35 + \frac{25}{30} = 35.83. \] Correct Answer: Median = 35.83.
Modal Class Calculation: The modal class is identified as the class with the highest frequency. From the table, the highest frequency is 30, which corresponds to the class $35 - 40$. Correct Answer: Modal class is $35 - 40$.
Class Interval | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 |
---|---|---|---|---|---|
Number of Students | 15 | 18 | 21 | 29 | 17 |
x | Less than 10 | Less than 20 | Less than 30 | Less than 40 | Less than 50 | Less than 60 |
f | 3 | 12 | 27 | 57 | 75 | 80 |
x | 5 | 10 | 15 | 20 | 25 |
f | 6 | 8 | 6 | y | 5 |
If the variance of the frequency distribution
xi | Frequency ft |
2 | 3 |
3 | 6 |
4 | 16 |
5 | \(\alpha\) |
6 | 9 |
7 | 5 |
8 | 6 |
is 3 , then $\alpha$ is equal to