Question

Statement I : To get a steady dc output from the pulsating voltage received from a full wave rectifier we can connect a capacitor across the output parallel to the load \(R_L\).
Statement II : To get a steady dc output from the pulsating voltage received from a full wave rectifier we can connect an inductor in series with \(R_L\).
In the light of the above statements, choose the most appropriate answer from the options given below :

• A. Both Statement I and Statement II are true
• B. Both Statement I and Statement II are false
• C. Statement I is true but Statement II is false
• D. Statement I is false but Statement II is true

Hint:

Capacitors block DC and bypass AC (parallel), whereas inductors block AC and allow DC (series). Combined (L-C filters), they provide even better stabilization.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
A rectifier converts AC to pulsating DC. To smooth these pulsations (ripples) and obtain a steady DC voltage, filter circuits using capacitors or inductors are used.
Step 2: Detailed Explanation:
Statement I: A capacitor filter works by charging during the peak of the pulsating voltage and discharging through the load when the voltage drops. Since it stores charge, it maintains a higher voltage level across the load, reducing ripples. It must be connected in parallel with the load. So Statement I is true.
Statement II: An inductor has the property of opposing any change in current. When placed in series with the load, it smooths out the variations in the current flow, effectively filtering the AC components out of the pulsating DC. So Statement II is true.
Step 3: Final Answer:
Both methods are valid techniques for filtering rectified voltage. Thus, both statements are true.