Statement-I : Aniline on reaction with concentrated \(H_2SO_4\) at 475 K gives p-amino benzene sulphonic acid. This gives blood red colour with Lassaigne’s test.
Statement-II : Aniline forms a salt with anhydrus \(AlCl_3\) in Friedel Craft’s reaction.
Statement-II : Aniline forms a salt with anhydrus \(AlCl_3\) in Friedel Craft’s reaction.
- Both Statement-I and Statement-II are correct.
- Both Statement-I and Statement-II are incorrect.
- Statement-I is correct and Statement-II incorrect.
- Statement-I is incorrect and Statement-II correct.
The Correct Option is A
Solution and Explanation
Top Questions on Amines
- Give plausible explanation for the following: (a) Diazonium salts of aromatic amines are stable.
(b) Aniline does not undergo Friedel–Crafts reaction.
(c) Aniline on nitration gives a substantial amount of meta product. - Assertion (A): Acetamide (structure: \(\text{C}_6\text{H}_5\text{NHCOCH}_3\)) is less basic than aniline.
Reason (R): Acetylation of aniline results in decrease of electron density on nitrogen. - The chemical test which can be used to distinguish between ethanamine and aniline is:
- If amines are arranged in increasing order of their basic strength in gaseous phase, the correct order will be:
Which of the following amines does not give foul smell of isocyanide on heating with chloroform and ethanolic KOH ?
Questions Asked in JEE Main exam
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
- JEE Main - 2025
- Molecular Orbital Theory
- The increase in pressure required to decrease the volume of a water sample by 0.2percentage is \( P \times 10^5 \, \text{Nm}^{-2} \). Bulk modulus of water is \( 2.15 \times 10^9 \, \text{Nm}^{-2} \). The value of \( P \) is ________________.
- JEE Main - 2025
- System of Particles & Rotational Motion
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
- JEE Main - 2025
- Kinetic Energy
- Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
- JEE Main - 2025
- Sequences and Series
- The value of current \( I \) in the electrical circuit as given below, when the potential at \( A \) is equal to the potential at \( B \), will be ________________________ A.
- JEE Main - 2025
- Electrical Circuits
JEE Main Notification
GMC Azamgarh Admission 2025: Dates, Courses, Fees, Eligibility, SelectJuly 22, 2025Concepts Used:
Amines - Chemical Properties
There are many chemical properties of amines.
The primary and secondary amines, including several amine derivatives, have a direct impact on their properties due to the presence of hydrogen bonding. The compounds containing phosphorus have a lower boiling point and the compounds containing amines and alcohol have a higher boiling point. The structure of alkanols is immensely similar to that of amine except the presence of the hydroxyl group. In such a case, oxygen has a higher electronegativity than that of nitrogen, so alkanol compounds are more acidic in nature in comparison to the amines.
On account of the ability to form hydrogen bonds, the amines have tendencies of high solubility in water. The amine molecules such as Ethyl, diethyl, triethyl, and Methyl are gaseous in nature. Whereas, higher weight amines have a solid structure and alkyl amines have a liquid structure. There is an ammonia smell to gaseous amines and a fishy smell to liquid amines. The solubility of amines entirely depends upon the number of carbon atoms in the molecule.