Question:

State Faraday's second law of electrolysis. How will the pH of aqueous NaCl solution be affected when it is electrolyzed?

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Faraday's second law relates the quantity of substance deposited to the amount of electricity passed. Electrolysis of NaCl leads to an increase in pH at the cathode and a decrease at the anode due to the generation of hydroxide and hydrogen ions.
Updated On: Feb 17, 2025
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Solution and Explanation

Faraday's Second Law of Electrolysis

Faraday’s second law of electrolysis: "The mass of a substance deposited or liberated at an electrode is directly proportional to the quantity of electricity passed through the electrolyte."

Electrolysis of Aqueous NaCl:

At the anode: 2Cl → Cl2(g) + 2e Chlorine gas (Cl2) is evolved, and the solution near the anode becomes more acidic (pH decreases).

At the cathode: 2H2O + 2e → H2(g) + 2OH Hydrogen gas (H2) is evolved, and the solution near the cathode becomes more alkaline (pH increases).

Explanation:

  • At the anode: Chlorine gas is produced, and the solution becomes acidic due to the formation of HCl, which lowers the pH.
  • At the cathode: Hydrogen gas is produced, and the solution becomes alkaline due to the formation of OH ions, which increases the pH.
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