Faraday’s second law of electrolysis: "The mass of a substance deposited or liberated at an electrode is directly proportional to the quantity of electricity passed through the electrolyte."
At the anode: 2Cl− → Cl2(g) + 2e− Chlorine gas (Cl2) is evolved, and the solution near the anode becomes more acidic (pH decreases).
At the cathode: 2H2O + 2e− → H2(g) + 2OH− Hydrogen gas (H2) is evolved, and the solution near the cathode becomes more alkaline (pH increases).
Consider the following half cell reaction $ \text{Cr}_2\text{O}_7^{2-} (\text{aq}) + 6\text{e}^- + 14\text{H}^+ (\text{aq}) \longrightarrow 2\text{Cr}^{3+} (\text{aq}) + 7\text{H}_2\text{O}(1) $
The reaction was conducted with the ratio of $\frac{[\text{Cr}^{3+}]^2}{[\text{Cr}_2\text{O}_7^{2-}]} = 10^{-6}$
The pH value at which the EMF of the half cell will become zero is ____ (nearest integer value)
[Given : standard half cell reduction potential $\text{E}^\circ_{\text{Cr}_2\text{O}_7^{2-}, \text{H}^+/\text{Cr}^{3+}} = 1.33\text{V}, \quad \frac{2.303\text{RT}}{\text{F}} = 0.059\text{V}$