Question:

Solve the system: \[ \begin{pmatrix} x \\ y \end{pmatrix} \quad \Rightarrow \quad \begin{pmatrix} 2x - 1 \\ 9 \end{pmatrix} \] Find the values of \(x\) and \(y\).

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When equating two column vectors, match and solve each component separately. Ensure the interpretation of arrows or transformations is consistent with the context.
  • \( x = 3, \, y = 9 \)
  • \( x = 1, \, y = 9 \)
  • \( x = 0, \, y = 9 \)
  • \( x = 3, \, y = 4 \)
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The Correct Option is A

Solution and Explanation

To find \( x \) and \( y \), we equate the corresponding components of the two column vectors:

From the first row: \[ x = 2x - 1 \] Simplifying: \[ -x = -1 \quad \Rightarrow \quad x = 1 \]

From the second row: \[ y = 9 \]

Therefore, the values are: \[ \boxed{x = 1, \quad y = 9.} \]

Final Answer:

\( x = 1, \; y = 9 \)

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