We need to graph the constraints and find the feasible region.
- From \( x - y \geq 0 \), we have \( x \geq y \).
- From \( x - 2y \geq -2 \), we have \( x \geq 2y - 2 \).
- The last constraint is \( x \geq 0, \, y \geq 0 \), which restricts the values to the first quadrant.
After plotting the constraints, the feasible region is formed, and we can evaluate \( Z = x + 2y \) at the vertices of the feasible region.
The vertex points are: (0, 0), (4, 2), (5, 3).
Now calculate \( Z \) at these points:
- At (0, 0), \( Z = 0 + 2(0) = 0 \).
- At (4, 2), \( Z = 4 + 2(2) = \).
- At (5, 3), \( Z = 5 + 2(3) = 11 \).
Thus, the maximum value of \( Z = 14 \) at the point (5, 3).