Given the differential equation:
\[ (x - y) \, dy - (x + y) \, dx = 0 \]
Rearrange the equation:
\[ (x - y) \, dy = (x + y) \, dx \]
Now, divide both sides by \( (x - y)(x + y) \):
\[ \frac{dy}{dx} = \frac{x + y}{x - y} \]
This is a **homogeneous equation** and can be solved using the substitution \( v = \frac{y}{x} \), where \( y = vx \). Hence, \( dy = v dx + x dv \).
Substitute into the equation:
\[ \frac{v dx + x dv}{dx} = \frac{x + vx}{x - vx} \] \[ v + x \frac{dv}{dx} = \frac{x(1 + v)}{x(1 - v)} \] \[ v + x \frac{dv}{dx} = \frac{1 + v}{1 - v} \]
Now, isolate the terms with \( dv \) on one side:
\[ x \frac{dv}{dx} = \frac{1 + v}{1 - v} - v \] Simplifying the right-hand side: \[ x \frac{dv}{dx} = \frac{1 + v - v(1 - v)}{1 - v} \] \[ x \frac{dv}{dx} = \frac{1 + v - v + v^2}{1 - v} \] \[ x \frac{dv}{dx} = \frac{1 + v^2}{1 - v} \] Now, the equation is ready to be solved by integrating both sides.
Continue solving by simplifying and performing the necessary integrations to obtain the solution of the differential equation.
For the curve \( \sqrt{x} + \sqrt{y} = 1 \), find the value of \( \frac{dy}{dx} \) at the point \( \left(\frac{1}{9}, \frac{1}{9}\right) \).