Question

Solution of a differential equation  \((1+ y2)dx=(\tan^{-1}y - x)dy\) is :

• A. \(ye^{\tan^{-1}y }= e^{\tan^{-1}y}(\tan^{-1}y + 1) + C\)
• B. \(ye^{\tan^{-1}y }= e^{\tan^{-1}y}(\tan^{-1}y - 1) + C\)
• C. \(xe^{\tan^{-1}y }= e^{\tan^{-1}y}(\tan^{-1}y + 1) + C\)
• D. \(xe^{\tan^{-1}y }= e^{\tan^{-1}y}(\tan^{-1}y - 1) + C\)

Answer 1

The Correct Option is C

The correct option is (C):\(xe^{\tan^{-1}y }= e^{\tan^{-1}y}(\tan^{-1}y - 1) + C\)