Question:
Sodium nitrate decomposes above $ \approx; 800^\circ C $ to give
Sodium nitrate decomposes above $ \approx; 800^\circ C $ to give
Updated On: Jun 14, 2022
- $ N_2 $
- $ O_2 $
- $ NO_2 $
- $ Na_2O $
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
$ NaNO_3 $ when heated, it decomposes in two stages as:
$ NaNO_3 \xrightarrow {T < 500^\circ C} NaNO_2 + \frac{1}{2} O_2 $
$ NaNO_2 \xrightarrow {T > 800^\circ C} Na_2O + N_2 + O_2 $
$ NaNO_3 \xrightarrow {T < 500^\circ C} NaNO_2 + \frac{1}{2} O_2 $
$ NaNO_2 \xrightarrow {T > 800^\circ C} Na_2O + N_2 + O_2 $
Was this answer helpful?
0
0
Top Questions on GROUP 1 ELEMENTS
- The compound which does not exist.
- JEE Main - 2023
- Chemistry
- GROUP 1 ELEMENTS
- Read the following two statements
Statement I: Ionic radius of Li+ is greater than Mg++
Statement II: Lithium and magnesium can't form superoxide- JEE Main - 2023
- Chemistry
- GROUP 1 ELEMENTS
Which of the following has the highest hydration energy?
- JEE Main - 2023
- Chemistry
- GROUP 1 ELEMENTS
- Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R:
Assertion A: Metallic sodium dissolved in liquid ammonia giving a deep blue solution which is paramagnetic.
Reasons R: The deep blue solution to the formation of amide.
In the light of the above statements, the correct answer from the options below:- NEET (UG) - 2023
- Chemistry
- GROUP 1 ELEMENTS
- In which form does \(BeCl_{2}\) exist in the solid state, vapor state and high temperature?
- JEE Main - 2023
- Chemistry
- GROUP 1 ELEMENTS
View More Questions
Questions Asked in JEE Advanced exam
- Consider the ellipse \(\frac{x^2}{9}+\frac{y^2}{4}=1\). Let S (p, q) be a point in the first quadrant such that \(\frac{p^2}{9}+\frac{q^2}{4}>1\). Two tangents are drawn from S to the ellipse, of which one meets the ellipse at one end point of the minor axis and the other meets the ellipse at a point T in the fourth quadrant. Let R be the vertex of the ellipse with positive x-coordinate and Obe the center of the ellipse. If the area of the triangle △ORT is \(\frac{3}{2}\) , then which of the following options is correct ?
- JEE Advanced - 2024
- Conic sections
- Among V(CO)6, Cr(CO)5, Cu(CO)3, Mn(CO)5, Fe(CO)5, [Co(CO)3]3-, [Cr(CO)4]4-, and Ir(CO)3, the total number of species isoelectronic with Ni(CO)4 is _________.
[Given, atomic number: V = 23, Cr=24, Mn 25, Fe 26, Co 27, Ni 28, Cu = 29, Ir = 77]- JEE Advanced - 2024
- Isomerism in Coordination Compounds
- Let \(\overrightarrow{OP}=\frac{\alpha-1}{\alpha}\hat{i}+\hat{j}+\hat{k},\overrightarrow{OQ}=\hat{i}+\frac{\beta-1}{\beta}\hat{j}+\hat{k}\) and \(\overrightarrow{OR}=\hat{i}+\hat{j}+\frac{1}{2}\hat{k}\) be three vector where α, β ∈ R - {0} and 0 denotes the origin. If \((\overrightarrow{OP}\times\overrightarrow{OQ}).\overrightarrow{OR}=0\) and the point (α, β, 2) lies on the plane 3x + 3y - z + l = 0, then the value of l is _______.
- JEE Advanced - 2024
- Vector Algebra
- A closed vessel contains 10 g of an ideal gas X at 300 K, which exerts 2 atm pressure. At the same temperature, 80 g of another ideal gas Y is added to it and the pressure becomes 6 atm. The ratio of root mean square velocities of X and Y at 300 K is
- JEE Advanced - 2024
- States of matter
- Let the function \(f:[1,\infin)→\R\) be defined by
\(f(t) = \begin{cases} (-1)^{n+1}2, & \text{if } t=2n-1,n\in\N, \\ \frac{(2n+1-t)}{2}f(2n-1)+\frac{(t-(2n-1))}{2}f(2n+1) & \text{if } 2n-1<t<2n+1,n\in\N. \end{cases}\)
Define \(g(x)=\int\limits_{1}^{x}f(t)dt,x\in(1,\infin).\) Let α denote the number of solutions of the equation g(x) = 0 in the interval (1, 8] and \(β=\lim\limits_{x→1+}\frac{g(x)}{x-1}\). Then the value of α + β is equal to _____.- JEE Advanced - 2024
- Integral Calculus
View More Questions