Sodium ethanoate \((CH₃COONa) \)when heated with soda lime (a mixture of sodium hydroxide and calcium oxide) undergoes decarboxylation to form methane \((CH₄)\).
The reaction is:
Therefore, 'X' is Methane.
Electrolysis of aqueous sodium ethanoate results in the formation of ethane \((C₂H₆)\) at the cathode, and the oxidation of the anion produces methane \((CH₄)\) at the anode.
The reactions are:
At the cathode: \(CH₃COO⁻ + H₂O → C₂H₆ + OH⁻\)
At the anode: \(CH₃COO⁻ → CH₄ + CO₂\)
Thus, 'X' is Methane and 'Y' is Ethane, making (A) Methane and Ethane the correct answer.
The increasing order of acid strength of the following carboxylic acids is:
\[
(i) \text{(CH}_3\text{)}_3\text{C-COOH} \quad (ii) \text{(CH}_3\text{)}_2\text{CH-COOH} \quad (iii) \text{CH}_3\text{CH}_2\text{COOH}
\]