Sodium ethanoate \((CH₃COONa) \)when heated with soda lime (a mixture of sodium hydroxide and calcium oxide) undergoes decarboxylation to form methane \((CH₄)\).
The reaction is:
Therefore, 'X' is Methane.
Electrolysis of aqueous sodium ethanoate results in the formation of ethane \((C₂H₆)\) at the cathode, and the oxidation of the anion produces methane \((CH₄)\) at the anode.
The reactions are:
At the cathode: \(CH₃COO⁻ + H₂O → C₂H₆ + OH⁻\)
At the anode: \(CH₃COO⁻ → CH₄ + CO₂\)
Thus, 'X' is Methane and 'Y' is Ethane, making (A) Methane and Ethane the correct answer.
When sodium ethanate (sodium acetate, CH₃COONa) is heated with soda lime (a mixture of sodium hydroxide and calcium oxide), a decarboxylation reaction occurs, which produces methane (CH₄). \[ CH₃COONa + NaOH \xrightarrow{\text{soda lime}} CH₄ + Na₂CO₃ \] When an aqueous solution of sodium ethanate is electrolyzed, it produces ethane (C₂H₆) because the electrolysis of sodium ethanate leads to the reduction of acetate ions to produce ethane. \[ CH₃COONa \xrightarrow{\text{electrolysis}} C₂H₆ \]
The increasing order of acid strength of the following carboxylic acids is:
\[
(i) \text{(CH}_3\text{)}_3\text{C-COOH} \quad (ii) \text{(CH}_3\text{)}_2\text{CH-COOH} \quad (iii) \text{CH}_3\text{CH}_2\text{COOH}
\]
In the given graph, \( E_a \) for the reverse reaction will be