Question

Sliding contact of a potentiometer is in the middle of the potentiometer wire having resistance \( R_p = 1 \, \Omega \) as shown in the figure. An external resistance of \( R_e = 2 \, \Omega \) is connected via the sliding contact.
The current \( i \) is : 

 

• A. 0.3 A
• B. 1.35 A
• C. 1.0 A
• D. 0.9 A

Hint:

For resistors in series and parallel, simplify the equivalent resistance and then use Ohm's law to calculate the current.

Answer 1

The Correct Option is C

The circuit can be considered as: \[ R_{\text{eq}} = 0.5 + \frac{0.5 \times 2}{2 + 0.5} = \frac{5}{10} + \frac{10}{25} \, \Omega = 0.9 \, \Omega \] Now, the current is: \[ i = \frac{0.9}{0.9} = 1 \, \text{A} \] Thus, the current is \( \boxed{1.0 \, \text{A}} \).