\(\frac{sin^8x-cos^8x}{1-2sin^2xcos^2x}\)=\(\frac{(sin^4x+cos^4x)(sin^4x-cos^4x)}{sin^2x+cos^2x-sin^2xcos^2x-sin^2xcos^2x}\)
=\(\frac{(sin^4x+cos^4x)(sin^4x-cos^4x)}{sin^x(1-cos^2x)+cos^2x(1-sin^2x)}\)
=\(-\frac{(sin^4x+cos^4x)(cos^2x-sin^2x}{sin^4x+cos^4x}\)
=-cos2x
∴\(\frac{sin^8x-cos^8x}{1-2sin^2xcos^2x}\)=∫-cos2xdx=-sin2\(\frac{x}{2}\)+C
परसेवा का आनंद — 120 शब्दों में रचनात्मक लेख लिखिए:
Answer the following questions:
[(i)] Explain the structure of a mature embryo sac of a typical flowering plant.
[(ii)] How is triple fusion achieved in these plants?
OR
[(i)] Describe the changes in the ovary and the uterus as induced by the changes in the level of pituitary and ovarian hormones during menstrual cycle in a human female.
Definite integral is an operation on functions which approximates the sum of the values (of the function) weighted by the length (or measure) of the intervals for which the function takes that value.
Definite integrals - Important Formulae Handbook
A real valued function being evaluated (integrated) over the closed interval [a, b] is written as :
\(\int_{a}^{b}f(x)dx\)
Definite integrals have a lot of applications. Its main application is that it is used to find out the area under the curve of a function, as shown below: