The provided information can be depicted in the following table.
A and C jointly obtained a total score of 7, with equal scores in all these parameters. Therefore, the possible combinations are either 1, 2, and 4 or 3, 3, and 1. Since Zooma has a score of 17, and all three countries in the happy category secured the highest score in exactly one parameter, Zooma can have a score of 7 in F, 6 in S, and 4 in C. This is because a score of 7 in S and 6 in C would be the scores of the other two countries, and Zooma cannot have a distribution of 7, 7, and 5, as there is no country that scored a 5 in C.
Amda can have a distribution of 3, 3, 1, or 4, 2, 1. In either case, the only possible score for F is 1, as no other parameter has a score of 1 for two countries.
The provided information can be depicted in the following table.
A and C jointly obtained a total score of 7, with equal scores in all these parameters. Therefore, the possible combinations are either 1, 2, and 4 or 3, 3, and 1. Since Zooma has a score of 17, and all three countries in the happy category secured the highest score in exactly one parameter, Zooma can have a score of 7 in F, 6 in S, and 4 in C. This is because a score of 7 in S and 6 in C would be the scores of the other two countries, and Zooma cannot have a distribution of 7, 7, and 5, as there is no country that scored a 5 in C.
As mentioned earlier, Zooma's score in C is determined to be 6.
The provided information can be depicted in the following table.
A and C jointly obtained a total score of 7, with equal scores in all these parameters. Therefore, the possible combinations are either 1, 2, and 4 or 3, 3, and 1. Since Zooma has a score of 17, and all three countries in the happy category secured the highest score in exactly one parameter, Zooma can have a score of 7 in F, 6 in S, and 4 in C. This is because a score of 7 in S and 6 in C would be the scores of the other two countries, and Zooma cannot have a distribution of 7, 7, and 5, as there is no country that scored a 5 in C.
In the provided table, Zoom achieved the highest scores with 7 in F, 6 in S, and 4 in C. The optimal remaining scores for Benga and Dalma could be:
As it is given that both had the same total score, it can only be 15 for both, i.e., Benga’s score in S or F was one less than the maximum possible.
The provided information can be depicted in the following table.
A and C jointly obtained a total score of 7, with equal scores in all these parameters. Therefore, the possible combinations are either 1, 2, and 4 or 3, 3, and 1. Since Zooma has a score of 17, and all three countries in the happy category secured the highest score in exactly one parameter, Zooma can have a score of 7 in F, 6 in S, and 4 in C. This is because a score of 7 in S and 6 in C would be the scores of the other two countries, and Zooma cannot have a distribution of 7, 7, and 5, as there is no country that scored a 5 in C.
Considering the scores of Zoom, Benga, and Delma as 17, 16, and 15, we get:
If Benga scores 16 and Dalma scores 15 (as illustrated in the previous solution), the highest possible values that remain are:
A | B | C | D | Average |
---|---|---|---|---|
3 | 4 | 4 | ? | 4 |
3 | ? | 5 | ? | 4 |
? | 3 | 3 | ? | 4 |
? | ? | ? | ? | 4.25 |
4 | 4 | 4 | 4.25 |