Ca → Ca2+ + 2e⁻
Cl + e⁻ → Cl⁻
One calcium atom loses 2 electrons → each electron is gained by a separate chlorine atom.
Thus, one calcium atom combines with two chlorine atoms:
Ca + 2Cl → Ca2+ + 2Cl⁻ → CaCl₂
The Ca2+ and Cl⁻ ions are held together by strong electrostatic (ionic) bonds to form solid calcium chloride.
Visual representation of electron transfer:
Ca (••) + 2 × Cl (•••••••) → Ca2+ [Cl (••••••••)]⁻ [Cl (••••••••)]⁻
(•• represents valence electrons; Cl gains 1 electron to complete its octet)
Calcium donates two electrons, chlorine atoms accept one electron each, forming an ionic compound CaCl₂ through complete transfer of electrons and formation of oppositely charged ions.
In the adjoining figure, \( AP = 1 \, \text{cm}, \ BP = 2 \, \text{cm}, \ AQ = 1.5 \, \text{cm}, \ AC = 4.5 \, \text{cm} \) Prove that \( \triangle APQ \sim \triangle ABC \).
Hence, find the length of \( PQ \), if \( BC = 3.6 \, \text{cm} \).