Question:
S and T are points on sides PR and QR of ΔPQR such that \(\angle\)P = \(\angle\)RTS. Show that ΔRPQ ~ ΔRTS.
S and T are points on sides PR and QR of ΔPQR such that \(\angle\)P = \(\angle\)RTS. Show that ΔRPQ ~ ΔRTS.
Updated On: Nov 2, 2023
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Solution and Explanation
Given: In ΔPQR, S and T are points on sides PR and QR
To Prove: ΔRPQ ~ ΔRTS
Proof: In ∆RPQ and ∆RST,
\(\angle\)RTS = \(\angle\)QPS (Given)
\(\angle\)R = \(\angle\)R (Common angle)
∴ ∆RPQ ∼ ∆RTS (By AA similarity criterion)
Hence Proved
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