Concept: Relative density (also known as specific gravity) of a substance is the ratio of its density to the density of a reference substance, which is usually water at \(4^\circ\text{C}\).
Relative Density (\(RD\)) = \(\frac{\text{Density of substance}}{\text{Density of water}}\).
Therefore, Density of substance = Relative Density \(\times\) Density of water.
Step 1: Identify the given values
Relative density of silver (\(RD_{silver}\)) = 10.8 (This is a dimensionless quantity).
Density of water (\(\rho_{water}\)) = \(10^3 \text{ kg m}^{-3}\) (which is \(1000 \text{ kg/m}^3\)).
We need to find the density of silver (\(\rho_{silver}\)).
Step 2: Use the formula relating density, relative density, and density of water
\[ \rho_{silver} = RD_{silver} \times \rho_{water} \]
Step 3: Substitute the given values and calculate
\[ \rho_{silver} = 10.8 \times 10^3 \text{ kg m}^{-3} \]
The density of silver is \(10.8 \times 10^3 \text{ kg/m}^3\).
Step 4: Compare with the options
(1) \(10.8 \times 10^3 \text{ kg/m}^3\): This matches our calculated value and has the correct units.
(2) \(10.8 \times 10^3 \text{ gm/cm}^3\): The numerical part might seem similar, but the unit is \(gm/cm^3\). The density of water in \(gm/cm^3\) is \(1 \text{ gm/cm}^3\). If we used that, density of silver would be \(10.8 \times 1 = 10.8 \text{ gm/cm}^3\). The value \(10.8 \times 10^3 \text{ gm/cm}^3\) is incorrect.
(3) \(10.8 \times 10^6 \text{ kg/m}^3\): Incorrect magnitude.
(4) \(10.8 \times 10^4 \text{ kg/m}^3\): Incorrect magnitude.
The correct density of silver is \(10.8 \times 10^3 \text{ kg/m}^3\).