Question:

Raju earns twice as much in March as in each of the other months of the year. What part of his annual earnings does he earn in that month?

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When one month is a multiple of the “usual” month, treat the usual month as $x$ and build the year from it; the $x$ cancels in the final fraction.
Updated On: Aug 12, 2025
  • $\dfrac{1}{5}$
  • $\dfrac{5}{7}$
  • $\dfrac{2}{13}$
  • $\dfrac{1}{10}$
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The Correct Option is C

Solution and Explanation

Step 1 (Model it): Let income in each of the other $11$ months be $x$. Then income in March $=2x$.
Step 2 (Total): Annual income $=11x+2x=13x$.
Step 3 (Required fraction): $\dfrac{\text{March}}{\text{Annual}}=\dfrac{2x}{13x}=\boxed{\dfrac{2}{13}}$.
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