Question

Radiation of frequency \(2ν_0\) is incident on a metal with threshold frequency \(ν_0\). The correct statement of the following is ______.

• A. No photoelectrons will be emitted
• B. All photoelectrons emitted will have kinetic energy equal to \(hν_0\)
• C. Maximum kinetic energy of photoelectrons emitted can be \(hν_0\)
• D. Maximum kinetic energy of photoelectrons emitted will be \(2hν_0\)

Answer 1

The Correct Option is C

According to Einstein’s photoelectric equation, the maximum kinetic energy \(K_{max}\) of the photoelectrons is given by:
\(K_{\text{max}} = h\nu - h\nu_0\)
where ν is the frequency of incident radiation and \(ν0 \)is the threshold frequency. If the radiation has a frequency \(2ν0\), then:
\(K_{\text{max}} = h(2\nu_0) - h\nu_0 = h\nu_0\)