Question:

Quantity A: The sum of integers from -6 to 7
Quantity B: The sum of integers from -7 to 6

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When calculating the sum of consecutive integers, you can group them symmetrically around 0 for quick calculations.
Updated On: Dec 13, 2025
  • If Quantity A is more than Quantity B
  • If Quantity A is equal to Quantity B
  • If Quantity A is less than Quantity B
  • If comparison can't be made from the information given
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The Correct Option is A

Solution and Explanation


Step 1: Calculate the sum of integers from -6 to 7.
The integers from -6 to 7 are: \[ -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7 \] The sum is: \[ -6 + (-5) + (-4) + (-3) + (-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 = 0 \] So, the sum of integers from -6 to 7 is 0. Step 2: Calculate the sum of integers from -7 to 6.
The integers from -7 to 6 are: \[ -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6 \] The sum is: \[ -7 + (-6) + (-5) + (-4) + (-3) + (-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 = -6 \] So, the sum of integers from -7 to 6 is -6. Step 3: Comparison.
Quantity A is 0, and Quantity B is -6. Clearly, 0 is greater than -6. Step 4: Conclusion.
Therefore, Quantity A is more than Quantity B, which corresponds to option (1).
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