Question:
Q is a point on the line BD dividing the segment internally. AB, PQ and CD are drawn perpendicular to BD. If AB = a, PQ = b and CD = c, then
Q is a point on the line BD dividing the segment internally. AB, PQ and CD are drawn perpendicular to BD. If AB = a, PQ = b and CD = c, then
Updated On: Apr 5, 2025
- \(\frac{1}{a} + \frac{1}{b} = \frac{1}{c}\)
- \(\frac{1}{a} + \frac{1}{c} = \frac{1}{b}\)
- \(\frac{1}{a} - \frac{1}{b} = \frac{1}{c}\)
- \(\frac{1}{b} + \frac{1}{c} = \frac{1}{a}\)
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The Correct Option is B
Solution and Explanation
The problem is related to the relation between the lengths of the perpendiculars and the segment divisions. According to the properties of similar triangles, the relation between the given distances can be expressed as: \[ \frac{1}{a} + \frac{1}{b} = \frac{1}{h} \]
The correct option is (B): \(\frac{1}{a} + \frac{1}{c} = \frac{1}{b}\)
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