Given: \(∠\)AOC + \(∠\)BOE = 70° and \(∠\)BOD = 40°
To find: \(∠\) BOE, and Reflex \(∠\)COE
From Figure,
(\(∠\)AOC +\(∠\)BOE +\(∠\)COE) and (\(∠\)COE +\(∠\)BOD +\(∠\)BOE) forms a straight line.
So, \(∠\)AOC+\(∠\)BOE +\(∠\)COE = \(∠\)COE +\(∠\)BOD+\(∠\)BOE = 180°
Now, by putting the values of \(∠\)AOC + \(∠\)BOE = 70° and \(∠\)BOD = 40° we get
\(∠\)COE = 110° and \(∠\)BOE = 30°
So, reflex \(∠\)COE = 360o – 110o = 250o
A driver of a car travelling at \(52\) \(km \;h^{–1}\) applies the brakes Shade the area on the graph that represents the distance travelled by the car during the period.
Which part of the graph represents uniform motion of the car?