Question

Probability of being 53 Sundays in any leap-year is:

• A. \(\frac{2}{7}\)
• B. \(\frac{3}{7}\)
• C. \(\frac{4}{7}\)
• D. \(\frac{5}{7}\)

Hint:

When calculating probabilities of specific days in a leap year, consider the extra days that determine the total number of Sundays.

Answer 1

The Correct Option is A

In a leap year, there are 366 days, which is equivalent to 52 full weeks and 2 extra days. For a leap year to have 53 Sundays, the extra days must include a Sunday. The extra days can be any of the following pairs: 1. Sunday and Monday 2. Monday and Tuesday 3. Tuesday and Wednesday 4. Wednesday and Thursday 5. Thursday and Friday 6. Friday and Saturday 7. Saturday and Sunday Thus, there are 2 favorable outcomes (Sunday-Monday and Saturday-Sunday) out of 7 possible outcomes. \[ P(\text{53 Sundays}) = \frac{2}{7} \] Thus, the probability is \(\frac{2}{7}\).