Question

Predict the output of the following code:

def ExamOn(mystr):
    newstr = ""
    count = 0
    for i in mystr:
        if count % 2 != 0:
            newstr = newstr + str(count - 1)
        else:
            newstr = newstr + i.lower()
        count += 1
    newstr = newstr + mystr[:2]
    print("The new string is:", newstr)

ExamOn("GenX")

Hint:

Use dry-run (tracing) to predict program behavior.
Check conditions like even/odd logic and concatenation carefully.

Answer 1

Let's trace the function step by step for the input "GenX".
Initial: newstr = "", count = 0
Iteration 1 (count = 0):
i = 'G'
Since 0%2 == 0 (even),
newstr = newstr + 'g' → newstr = "g"
count = 1
Iteration 2 (count = 1):
i = 'e'
1%2 ≠ 0 (odd), so add count - 1 = 0
newstr = "g" + "0" → newstr = "g0"
count = 2
Iteration 3 (count = 2):
i = 'n'
2%2 == 0 → newstr = "g0" + "n" → newstr = "g0n"
count = 3
Iteration 4 (count = 3):
i = 'X'
3%2 ≠ 0 → newstr = "g0n" + "2" → newstr = "g0n2"
count = 4
After the loop: mystr[:2] = "Ge"
newstr = "g0n2" + "Ge" → newstr = "g0n2Ge"
Final output: The new string is: g0n2Ge
% Final Answer Output: The new string is: g0n2Ge