To calculate power, you can use the formula \(P = \frac {V^2}{R}\),
Where V is the voltage and R is the resistance.
The power dissipated across the 8 Ω resistor is 2 W.
voltage across the 8 Ω resistor:
\(2 = \frac {V^2}{8}\)
\(V^2 = 16 \ V\)
\(V =\sqrt { 16} \ V\)
\(V = 4 \ V\)
Now, power dissipated across the 3 Ω resistor:
\(P = \frac {V^2}{R}\)
\(P = \frac {4^2}{3}\)
P= 16/3 W.
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec:
Current electricity is defined as the flow of electrons from one section of the circuit to another.
There are two types of current electricity as follows:
The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.
The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.