Question:

Power dissipated across the 8 Ω resistor in the circuit shown here is 2 W. The power dissipated in watt units across the 3 Ω resistor is:
Power dissipated across the 8 Ω resistor in the circuit

Updated On: Oct 21, 2023
  • 6
  • 1.5
  • 0.45
  • 3
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

To calculate power, you can use the formula \(P = \frac {V^2}{R}\),
Where V is the voltage and R is the resistance. 
The power dissipated across the 8 Ω resistor is 2 W. 
voltage across the 8 Ω resistor: 
\(2 = \frac {V^2}{8}\)
\(V^2 = 16 \ V\)
\(V =\sqrt { 16} \ V\)
\(V = 4 \ V\)
Now, power dissipated across the 3 Ω resistor:
\(P = \frac {V^2}{R}\)

\(P = \frac {4^2}{3}\) 

P= 16/3 W.

 

Was this answer helpful?
0
0

Top Questions on Current electricity

View More Questions

Questions Asked in NEET exam

View More Questions

Concepts Used:

Current Electricity

Current electricity is defined as the flow of electrons from one section of the circuit to another.

Types of Current Electricity

There are two types of current electricity as follows:

Direct Current

The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.

Alternating Current

The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.