Question:

Plot the graph between \( \frac{1}{u} \) and \( \frac{1}{v} \) for the given concave mirror and then evaluate focal length by graph.

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When drawing the graph, choose scales that utilize at least two-thirds of the graph paper area for better accuracy. The best-fit line should be drawn such that there is an equal distribution of points on either side of the line. Do not force the line to pass through the origin.
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Solution and Explanation

Step 1: Understanding the Concept: 
This experiment is a graphical method to determine the focal length of a concave mirror. It uses the data of object distance (u) and image distance (v) obtained from the two-pin method. By plotting \( \frac{1}{v} \) against \( \frac{1}{u} \), we can use the intercepts of the resulting straight-line graph to calculate the focal length, which often provides a more accurate result than averaging individual calculations. 
Step 2: Key Formula and Apparatus: 
Apparatus Required: 
The same as for the two-pin method: an optical bench, a concave mirror, a mirror holder, two optical needles (pins), and a meter scale. Also, a graph paper is needed. 
Key Formula: 
The mirror formula is: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] This can be rearranged into the form of a straight-line equation \( y = mx + c \): \[ \frac{1}{v} = -\frac{1}{u} + \frac{1}{f} \] Comparing this with \( y = mx + c \), we have: - \( y = \frac{1}{v} \) - \( x = \frac{1}{u} \) - Slope \( m = -1 \) - Y-intercept \( c = \frac{1}{f} \) 
When \( \frac{1}{v} = 0 \), we get the X-intercept as \( \frac{1}{u} = \frac{1}{f} \). 
Step 3: Detailed Procedure: 
1. Data Collection: 
- Perform the experiment to find the focal length of the concave mirror using the two-pin method (as in Question 1). 
- Obtain at least 5-6 sets of readings for object distance (u) and the corresponding image distance (v). 
2. Data Processing: 
- For each pair of (u, v), calculate their reciprocals: \( x = \frac{1}{u} \) and \( y = \frac{1}{v} \). 
- Tabulate the results. 
 

3. Plotting the Graph: 
- Choose a suitable scale for both axes on the graph paper. 
- Plot the graph with \( \frac{1}{u} \) along the X-axis and \( \frac{1}{v} \) along the Y-axis. 
- The plotted points should lie on a straight line. Draw the best-fit straight line passing through these points. 
- The line will have a negative slope and will intersect both the positive X and Y axes. 

Step 4: Calculation from Graph and Final Answer: 
1. Finding Intercepts: 
- Find the Y-intercept (OA) where the line cuts the Y-axis (\( \frac{1}{u} = 0 \)). 
- Find the X-intercept (OB) where the line cuts the X-axis (\( \frac{1}{v} = 0 \)). 
2. Calculating Focal Length: 
- From the Y-intercept: \( OA = \frac{1}{f} \implies f_1 = \frac{1}{OA} \). 
- From the X-intercept: \( OB = \frac{1}{f} \implies f_2 = \frac{1}{OB} \). 
- The focal length of the mirror is the mean of these two values: \[ f = \frac{f_1 + f_2}{2} \] The result is stated as: "The focal length of the concave mirror as determined from the graph is f cm." 
 

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